Mixture:
By using the above method I hope you can solved any problems on
allegation.
Ok
,lets see some examples.
Q.A merchant has 1000kg
of sugar,part of which he sells at 8%
profits and the rest of it at 18% profit. He gain 14% on the whole.Find the
quantity sold at 18 % profit.
Ans:Remember if you used the normal
process,it will make you more complicated.just follow the above formula.
Here,
A=8
B=18
M=14
4:6
=2:3
=>2:3=1000(given)
=>2+3=1000
=>5=1000
=>1=200
Therefore, quantity sold at
18%=200*3=600.
Q.The average
salary per head of the entire staff including officer and clerk is Rs.60. The
average of officer salary per head is
Rs.400 and that of clerk is Rs.56.If the number of officer is 12.find the
number of clerk.
Ans:
A=400
B=56
M=60
=>4:340
=>1:85
Which means that for every 1 officer
there is 85 clerk.
So, number of clerk is=85*12=1020
Q.A sum of Rs.41 was divided among 50 boys and
girls,each boy get 90 paise and a
girl 60 paise.Find the number of boys.
Rs.41=4100
paise.
17:8=50
17+8=50
25=50
1=2
Boys=17*2=34
Girls=8*2=16
Q.Ramesh has
Rs.3600, he invest a part of it at 3% per anum and the remaing at 5% higher rate of interest.He get in all Rs.540
at the end of 3years.Find the sum invested at 3% per anum.
Ans: The problem is based on Rate of
interest.
P=Rs.3600 S.I=540,
Time=3yrs Rate=? SI=p*r*t 540=3600*r*3
100 100
R=5%
3:2
=>3+2=3600
=>5=3600
=>1=720
Sum invested in 3%=720*3=2160.
Q.A man purchase a horse and a cow for
Rs.50000,he sell the horse at a profit of 20% and the cow at 10% loss.If he
gain 2% for the whole transaction.Find the cost price of the horse.
Ans:
Horse=20%(profit) cow=-10(loss)
12:18
=>2:3
=>2+3=50000
=>1=10000 cost price of
horse=10000*2=20000Rs.
Q.In an examination a student get 3 marks for each correct
answer and loss 1 mark for every wrong answer.He score zero mark in a paper of
100 question.How many of his answer was right.
Ans:
1:3
=>1+3=100
=>4=100
=>1=25 therefore Number of correct answer=25*1=25
Q.A merchant
sold 20 dozen oranges.He sold some at 4% loss and the rest at the cost price.He
loss 3% on the whole transaction.Find the quantity sold at loss.
Ans: from the given question we know
that, the cost price of the oranges is 0.
3:1
=>4=80
=>1=20
The quantity sold at loss
price=20*3=60dozen
Conditional questions:
Q.A container contains 80lit
of milk.8 litre of milk was taken out and replace by water.This process replace two times. How muck milk is now containing in the container.
Ans:
Q.In a 40 litre of milk and water ,10% is water.How
much water must be added to make the water 28% in the new mixture.
Ans: Lt(y%x-% / 100-y%)
40(28%-10% / 100-28%)
=40 x 18/72
=10lt.
